Programming in Python, OPPE 1

January 2025 term, Set 4

Quiz Space

MusicOpen the study music controls.

CalculatorOpen the calculatorLearning mode

Question 1

+10−0Instructions

QuestionTest casesSolution

Given two angles of a triangle (theta_1 and theta_2) in degrees, determine if the triangle is obtuse. A triangle is obtuse if it has one angle greater than 90 degrees.

Examples

>>> is_obtuse(30, 60) # other angle is 90 so right triangle
False
>>> is_obtuse(100, 40) # has an angle 100, so obtuse
True
>>> is_obtuse(30, 30) # other angle is 120, so obtuse
True
>>> is_obtuse(60, 45) # other angle is 75, so acute
False

Your task

Implement this function:

def is_obtuse(theta_1: int, theta_2: int) -> bool:

Write the function only — the arguments are read for you and the return value is printed automatically.

Arguments arrive as one Python literal per line, in this order: theta_1, theta_2.

Example

Input

30
60

Output

False

Code Editor

Python 3

−14+

ResetNot submitted

def is_obtuse(theta_1: int, theta_2: int) -> bool:
    '''
    Check if a triangle is obtuse given two angles.

    Args:
        theta_1 (int): The first angle of the triangle.
        theta_2 (int): The second angle of the triangle.

    Returns:
        bool: True if the triangle is obtuse, False otherwise.

    Examples:
    >>> is_obtuse(30, 60)
    False
    >>> is_obtuse(30, 30)
    True
    >>> is_obtuse(100, 40)
    True
    >>> is_obtuse(60, 45)
    False
    '''
    ...

def is_obtuse(theta_1: int, theta_2: int) -> bool: ''' Check if a triangle is obtuse given two angles. Args: theta_1 (int): The first angle of the triangle. theta_2 (int): The second angle of the triangle. Returns: bool: True if the triangle is obtuse, False otherwise. Examples: >>> is_obtuse(30, 60) False >>> is_obtuse(30, 30) True >>> is_obtuse(100, 40) True >>> is_obtuse(60, 45) False ''' ...

Run sample testsSubmit

Submit this paper?

You cannot change your answers after submitting.

Answered

0

Not answered

1

Marked for review

0

Answered & marked for review

0

Not visited

2

Keep goingSubmit paper

Instructions

The palette shows the status of every question. Pick a number to go straight to it.

Answered

0

Not answered

1

Marked for review

0

Answered & marked for review

0

Not visited

2

• Save & Next moves to the next question. Answers are saved as you go.
• Mark for Review & Next flags the question to come back to. A flagged answer still counts.
• Clear Response removes your answer to the question on screen.
• The ← and → keys move to the previous and next question.

Given two angles of a triangle (theta_1 and theta_2) in degrees, determine if the triangle is obtuse. A triangle is obtuse if it has one angle greater than 90 degrees. ### Examples ``` >>> is_obtuse(30, 60) # other angle is 90 so right triangle False >>> is_obtuse(100, 40) # has an angle 100, so obtuse True >>> is_obtuse(30, 30) # other angle is 120, so obtuse True >>> is_obtuse(60, 45) # other angle is 75, so acute False ``` ## Your task Implement this function: ```python def is_obtuse(theta_1: int, theta_2: int) -> bool: ``` Write the function only — the arguments are read for you and the return value is printed automatically. **Arguments** arrive as one Python literal per line, in this order: `theta_1`, `theta_2`. ## Example **Input** ``` 30 60 ``` **Output** ``` False ``` Given a string containing a Markdown image link of the format , convert it to a proper HTML image tag of the format <img src="image_url" alt="alt text">. ### Examples ``` >>> markdown_to_html_image("") '<img src="dog.jpg" alt="awesome dog">' >>> markdown_to_html_image("") '<img src="python.png" alt="python logo">' ``` ## Your task Implement this function: ```python def markdown_to_html_image(markdown_image: str) -> str: ``` Write the function only — the arguments are read for you and the return value is printed automatically. **Arguments** arrive as one Python literal per line, in this order: `markdown_image`. ## Example **Input** ``` "" ``` **Output** ``` '<img src="dog.jpg" alt="awesome dog">' ``` Write a function remove_n_elems_from_index that takes a tuple t, an integer n, and an index i as input. The function should return a new tuple with the n elements starting at index i removed. If the index i is out of bounds, return the original tuple. NOTE: This is a function type question, you don't have to take input or print the output, just have to complete the required function definition. ### Examples ``` >>> remove_n_elems_from_index((1, 2, 3, 4, 5), 2, 1) (1, 4, 5) >>> remove_n_elems_from_index((10, 20, 30, 40, 50), 3, 2) (10, 20, 30) >>> remove_n_elems_from_index((1, 2, 3, 4, 5), 5, 0) () ``` ## Your task Implement this function: ```python def remove_n_elems_from_index(t: tuple, n: int, i: int) -> tuple: ``` Write the function only — the arguments are read for you and the return value is printed automatically. **Arguments** arrive as one Python literal per line, in this order: `t`, `n`, `i`. ## Example **Input** ``` (1, 2, 3, 4, 5) 2 1 ``` **Output** ``` (1, 4, 5) ```